A uniform solid cylinder of mass $M$ and radius $R$ rotates about a frictionless horizontal axle. Two similar masses suspended with the help two ropes wrapped around the cylinder. If the angular velocity of the cylinder, after the masses fall down through distance $h$, will be
$\frac{1}{R}\sqrt {8mgh/(M + 4m)} $
$\frac{1}{R}\sqrt {8mgh/(M + m)} $
$\frac{1}{R}\sqrt {mgh/(M + m)} $
$\frac{1}{R}\sqrt {8mgh/(M + 2m)} $
A uniformly thick wheel with moment of inertia $I$ and radius $R$ is free to rotate about its centre of mass (see fig). A massless string is wrapped over its rim and two blocks of masses $\mathrm{m}_{1}$ and $\mathrm{m}_{2}\left(\mathrm{m}_{1}>\mathrm{m}_{2}\right)$ are attached to the ends of the string. The system is released from rest. The angular speed of the wheel when $\mathrm{m}_{1}$ descents by a distance $h$ is
What is pure translational motion ?
Let $\mathop A\limits^ \to $ be a unit vector along the axis of rotation of a purely rotating body and $\mathop B\limits^ \to $ be a unit vector along the velocity of a particle $ P$ of the body away from the axis. The value of $\mathop A\limits^ \to .\mathop B\limits^ \to $ is
For the given figure find the acceleration of $1\, kg$ block if string is massless and mass of the pulley is $2\, kg$ and diameter of puller is $0.2\, m$ (in $m / s ^{2}$)
“Integration is zero for a point of homogeneous body' which is that point ?