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14.Semiconductor Electronics
hard
A Zener diode is connected to a battery and a load as show below: The currents, $I, I_Z$ and $I_L$ are respectively .
A
$15\,mA, 5\,mA, 10\, mA$
B
$15\,mA, 7.5\,mA, 7.5\, mA$
C
$12.5\,mA, 5\,mA, 7.5\, mA$
D
$12.5\,mA, 7.5\,mA, 5\, mA$
(JEE MAIN-2014)
Solution
Here, $R=4 \mathrm{k} \Omega=4 \times 10^{3} \Omega$
$V_{i}=60 \mathrm{V}$
Zener voltage $V_{z}=10 \mathrm{V}$ $R_{L}=2 \mathrm{k} \Omega=2 \times 10^{3} \Omega$
Load current, $I_{\mathrm{L}}=\frac{V_{Z}}{R_{L}}=\frac{10}{2 \times 10^{3}}=5 \mathrm{\,mA}$
Current through $R, I=\frac{V_{i}-V_{Z}}{R}$
$=\frac{60-10}{4 \times 10^{3}}=\frac{50}{4 \times 10^{3}}=12.5 \mathrm{\,mA}$
Fom circuit diagram,
$I=I_{z}+I_{L}$
$\Rightarrow 12.5=I_{z}+5$
$\Rightarrow I_Z\,=\,12.5-5\,=\,7.5\,mA$
Standard 12
Physics
