An alternating voltage $v\left( t \right) = 220\,\sin \,100\pi l\,volt$ is applied to a purely resistive load of $50\,\Omega $ . The time taken for the current to rise from half of the peak value of the peak value is.....$ms$

A generator produces a voltage that is given by $V = 240\,sin \,120\,t$, where t is in seconds. The frequency and $ r.m.s.$ voltage are

An $AC$ source rated $220\, V , 50\, Hz$ is connected to a resistor. The time taken by the current to change from its maximum to the rms value is

An AC source is rated $222 \,V , 60 \,Hz$. The average voltage is calculated in a time interval of $16.67 \,ms$. It

What is $rms$ ? Write the formula of $rms $ for current ? 

Three alternating voltage sources $V_1$ = $3 sin \omega t $ volt , $V_2= 5  sin(\omega t + \phi _1)$ volt and $V_3 = 5  sin(\omega t -\phi_2 )$ volt connected across a resistance $R= \sqrt {\frac{7}{3}} \Omega $ as shown in the figure (where $ \phi_1$  and $ \phi_2$   corresponds to $30^o $ and $127^o $ respectively). Find the peak current (in Amp) through the resistor