Gujarati
Hindi
2. Electric Potential and Capacitance
medium

An electric charge $10^{-8}\  C$  is placed at the point $ (4\,m, 7\,m, 2\,m)$. At the point $(1\,m, 3\,m, 2\,m)$, the electric

A

potential will be $18\, V$

B

field has no $Y-$ component

C

field will be along $Z-$ axis

D

potential will be $1.8 \,V$

Solution

$V=\frac{K Q}{r}=\frac{9 \times 10^{9} \times 10^{-8}}{\sqrt{(1-4)^{2}+(3-7)^{2}+(2-2)^{2}}}=18 V$

and electric field lines will be in all three direction.

Standard 12
Physics

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