An electric field of $1500\, V/m$ and a magnetic field of $0.40\, weber/metre^2$ act on a moving electron. The minimum uniform speed along a straight line the electron could have is
$1.6 \times 10^{15} \,m/s$
$6 \times 10^{-16} \,m/s$
$3.75 \times 10^{3} \,m/s$
$3.75 \times 10^{2} \,m/s$
Which particles will have minimum frequency of revolution when projected with the same velocity perpendicular to a magnetic field
An electron moving towards the east enters a magnetic field directed towards the north. The force on the electron will be directed
At $t = 0$ a charge $q$ is at the origin and moving in the $y-$ direction with velocity $\overrightarrow v = v\,\hat j .$ The charge moves in a magnetic field that is for $y > 0$ out of page and given by $B_1 \hat z$ and for $y < 0$ into the page and given $-B_2 \hat z .$ The charge's subsequent trajectory is shown in the sketch. From this information, we can deduce that
Two charged particles, having same kinetic energy, are allowed to pass through a uniform magnetic field perpendicular to the direction of motion. If the ratio of radii of their circular paths is $6: 5$ and their respective masses ratio is $9: 4$. Then, the ratio of their charges will be.
An electron enters a magnetic field whose direction is perpendicular to the velocity of the electron. Then