An electric field of 1500, V/m and a magnetic | vedclass

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Question

When the electron moves in both electric and magnetic fields then :

$\mathrm{q} \mathrm{E}=\mathrm{qvB}$

$	herefore $ $v=$ $\frac{E}{B}-\frac{1

Vedclass · Accepted Answer

$3.75 	imes 10^{3} \,m/s$

Vedclass · Answer

When the electron moves in both electric and magnetic fields then :

$\mathrm{q} \mathrm{E}=\mathrm{qvB}$

$	herefore $ $v=$ $\frac{E}{B}-\frac{1500}{0.40}=370\, \mathrm{m} / \mathrm{s}$

$=3.75 	imes 10^{3}\, \mathrm{m} / \mathrm{s}$

An electric field of $1500\, V/m$ and a magnetic field of $0.40\, weber/metre^2$ act on a moving electron. The minimum uniform speed along a straight line the electron could have is

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