An electron beam is moving between two parallel plates having electric field 1.125 × {10^{ - 6}}N/m

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11.Dual Nature of Radiation and matter

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An electron beam is moving between two parallel plates having electric field $1.125 \times {10^{ - 6}}N/m$. A magnetic field $3 \times {10^{ - 10}}T$ is also applied so that beam of electrons do not deflect. The velocity of the electron is ............ $m/s$

A

$4225$

B

$3750$

C

$2750$

D

$3200$

Solution

(b) $v = \frac{E}{B} = \frac{{1.125 \times {{10}^{ – 6}}}}{{3 \times {{10}^{ – 10}}}} = 3750\,m/s$

Standard 12

Physics

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