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13.Oscillations
medium
An ideal spring with spring-constant $K$ is hung from the ceiling and a block of mass $M$ is attached to its lower end. The mass is released with the spring initially unstretched. Then the maximum extension in the spring is
A
$4 Mg/K$
B
$2 Mg/K$
C
$Mg/K$
D
$Mg/2K$
(IIT-2002)
Solution

(b) Let $x$ be the maximum extension of the spring. From energy conservation
Loss in gravitational potential energy = Gain in potential energy of spring
$Mgx = \frac{1}{2}K{x^2}$
$ \Rightarrow x = \frac{{2Mg}}{K}$
Standard 11
Physics
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