An iron bar of length $L$ has magnetic moment $M$. It is bent at the middle of its length such that the two arms make an angle $60^{\circ}$ with each other. The magnetic moment of this new magnet is :
$\frac{M}{2}$
$2 M$
$\frac{M}{\sqrt{3}}$
$M$
Two equal bar magnets are kept as shown in the figure. The direction of resultant magnetic field, indicated by arrow head at the point $P$ is (approximately)
In two separate experiments the neutral points due to two small magnets are at a distance of $r$ and $ 2r$ n broad side-on position. The ratio of their magnetic moments will be
The magnetic field due to a short magnet at a point on its axis at distance $X \,cm $ from the middle point of the magnet is $200 $ $Gauss$. The magnetic field at a point on the neutral axis at a distance $ X \,cm$ from the middle of the magnet is.....$Gauss$
Due to a small magnet intensity at a distance $x$ in the end on position is $9$ $Gauss$. What will be the intensity at a distance $\frac{x}{2}$ on broad side on position..... $Gauss$
Two short magnets with their axes horizontal and perpendicular to the magnetic meridian are placed with their centres $40\, cm$ east and $ 50\,cm$ west of magnetic needle. If the needle remains undeflected, the ratio of their magnetic moments ${M_1}:{M_2}$ is