5.Magnetism and Matter
medium

An iron bar of length $L$ has magnetic moment $M$. It is bent at the middle of its length such that the two arms make an angle $60^{\circ}$ with each other. The magnetic moment of this new magnet is :

A

$\frac{M}{2}$

B

$2 M$

C

$\frac{M}{\sqrt{3}}$

D

$M$

(NEET-2024)

Solution

(image)

$M=m I$.

(image)

$\Delta l=2 \frac{l}{2} \sin 30^{\circ}$

$=\frac{l}{2}$

$M^{\prime}=m / / 2$

$=M / 2$

Standard 12
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.