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5.Magnetism and Matter
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An iron bar of length $L$ has magnetic moment $M$. It is bent at the middle of its length such that the two arms make an angle $60^{\circ}$ with each other. The magnetic moment of this new magnet is :
A
$\frac{M}{2}$
B
$2 M$
C
$\frac{M}{\sqrt{3}}$
D
$M$
(NEET-2024)
Solution

(image)
$M=m I$.
(image)
$\Delta l=2 \frac{l}{2} \sin 30^{\circ}$
$=\frac{l}{2}$
$M^{\prime}=m / / 2$
$=M / 2$
Standard 12
Physics
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