An object, moving with a speed of $6.25\, m/s$, is decelerated at a rate given by
$\frac{{dv}}{{dt}} =  - 2.5\sqrt v$
where $v$ is the instantaneous speed. The time taken by the object, to come to rest, would be ........$s$

  • A
    $4$
  • B
    $8$
  • C
    $1$
  • D
    $2$

Similar Questions

The ratio of displacement in $n$ second and in the $n^{th}$ second for a particle moving in a straight line under constant acceleration starting from rest is 

A point moves with uniform acceleration and $\upsilon _1,\upsilon _2$ and $\upsilon _3$ denote the average velocities in the three successive intervals of time $t_1, t_2$ and $t_3$. Which of the following relations is correct

A ball is dropped from a bridge $122.5\, metres$ above a river. After the ball has been falling for two seconds, a second ball is thrown straight down after it. What must its initial velocity be so that both hit the water at the same time?.......$m/s$

The displacement $x$ of a particle varies with time $t$ as $x = a{e^{ - \alpha t}} + b{e^{\beta t}}$ , where $a, b, \alpha$ and $\beta $ are positive constants. The velocity of the particle will

A frictionless wire $AB$ is fixed on a circle of radius $R$. A very small bead slips on  this wire. Time taken by bead to slip from $A$ to $B$ is