An object with a mass 10 ,kg moves at a constant velocity of 10 ,m/sec . A constant force then acts

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2.Motion in Straight Line

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An object with a mass $10 \,kg$ moves at a constant velocity of $10 \,m/sec$. A constant force then acts for $4\, second$ on the object and gives it a speed of $2\, m/sec$ in opposite direction. The acceleration produced in it, is ........ $m/{\sec ^2}$

A

$3$

B

$ - 3$

C

$0.3$

D

$ - 0.3$

Solution

(b)$\vec a = \frac{{\overrightarrow {{v_2}} – \overrightarrow {{v_1}} }}{t} = \frac{{( – 2) – ( + 10)}}{4} = \frac{{ – 12}}{4} = – 3\;m/{s^2}$

Standard 11

Physics

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