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2. Electric Potential and Capacitance
easy
As per this diagram a point charge $ + q$ is placed at the origin $O$. Work done in taking another point charge $ - Q$ from the point $A$ [co-ordinates $(0,\,a)$] to another point $B$ [co-ordinates $(a, 0)$] along the straight path $AB$ is
A
$Zero$
B
$\left( {\frac{{ - qQ}}{{4\pi {\varepsilon _0}}}\frac{1}{{{a^2}}}} \right)\,\sqrt 2 a$
C
$\left( {\frac{{qQ}}{{4\pi {\varepsilon _0}}}\frac{1}{{{a^2}}}} \right)\,\frac{a}{{\sqrt 2 }}$
D
$\left( {\frac{{qQ}}{{4\pi {\varepsilon _0}}}\frac{1}{{{a^2}}}} \right)\,\sqrt 2 a$
(AIPMT-2005)
Solution
(a)Since $A$ and $B$ are at equal potential so potential difference between $A$ and $B$ is zero. Hence $W = Q.\Delta V = 0$
Standard 12
Physics
