Assertion : A deuteron and an alpha - particl | vedclass

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Question

$\mathrm{q}_{\mathrm{d}}=\mathrm{e}, \mathrm{m}_{\mathrm{d}}=2 \mathrm{m}_{\mathrm{p}}=2\, \mathrm{m}$

$\mathrm{q}_{\alpha}=2 \mathrm{e}, \mathrm{m

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If Assertion is correct but Reason is incorrect.

Vedclass · Answer

$\mathrm{q}_{\mathrm{d}}=\mathrm{e}, \mathrm{m}_{\mathrm{d}}=2 \mathrm{m}_{\mathrm{p}}=2\, \mathrm{m}$

$\mathrm{q}_{\alpha}=2 \mathrm{e}, \mathrm{m}_{\alpha}=4 \mathrm{m}_{\mathrm{p}}=4 \,\mathrm{m}$

$\mathrm{F}_{1}=\mathrm{F}_{\alpha}=\mathrm{eE}, \mathrm{F}_{2}=\mathrm{F}_{\alpha}=2 \mathrm{eE} 
eq \mathrm{F}_{1}$

Further, $\quad a_{1}=\frac{F_{1}}{2 m}=\frac{e E}{2 m}$

and $a_{2}=\frac{F_{2}}{2 m}=\frac{2 e E}{4 m}=\frac{e E}{2 m}=a_{1}$

Assertion : A deuteron and an $\alpha -$ particle are placed in an electric field. If $F_1$ and $F_2$ be the forces acting on them and $a_1$ and $a_2$ be their accelerations respectively then, $a_1 = a_2$.

Reason : Forces will be same in electric field

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