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14.Probability
hard
Assume that each born child is equally likely to be a boy or a girl. If two families have two children each, then the conditional probability that all children are girls given that at least two are girls is
A
$\frac{1}{10}$
B
$\frac{1}{17}$
C
$\frac{1}{12}$
D
$\frac{1}{11}$
(JEE MAIN-2019)
Solution
$P(B o y)=P(g i r l)=\frac{1}{2}$
Required probability $=\frac{\text { all four girls }}{\text { Atleast two girls }}$
$=\frac{\left(\frac{1}{2}\right)^{4}}{\left(\frac{1}{2}\right)^{4}+^{4} \mathrm{C}_{3}\left(\frac{1}{2}\right)^{4}+^{4} \mathrm{C}_{2}\left(\frac{1}{2}\right)^{4}}$
$=\frac{1}{11}$
Standard 11
Mathematics