14.Probability
hard

Assume that each born child is equally likely to be a boy or a girl. If two families have two children each, then the conditional probability that all children are girls given that at least two are girls is

A

$\frac{1}{10}$

B

$\frac{1}{17}$

C

$\frac{1}{12}$

D

$\frac{1}{11}$

(JEE MAIN-2019)

Solution

$P(B o y)=P(g i r l)=\frac{1}{2}$

Required probability $=\frac{\text { all four girls }}{\text { Atleast two girls }}$

$=\frac{\left(\frac{1}{2}\right)^{4}}{\left(\frac{1}{2}\right)^{4}+^{4} \mathrm{C}_{3}\left(\frac{1}{2}\right)^{4}+^{4} \mathrm{C}_{2}\left(\frac{1}{2}\right)^{4}}$

$=\frac{1}{11}$

Standard 11
Mathematics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.