At a given instant, A is moving with velocity | vedclass

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Question

$l_{1}=2 l_{2}+l_{3}=$ constant

$\frac{d l_{1}}{d t}+2 \frac{d l_{2}}{d t}+\frac{d l_{3}}{d t}=0$

$-5+2(-5)+\frac{d l}{d t}=0$

$\frac{d l_{3}

Vedclass · Accepted Answer

$15\,\, m/s \downarrow  $

Vedclass · Answer

$l_{1}=2 l_{2}+l_{3}=$ constant

$\frac{d l_{1}}{d t}+2 \frac{d l_{2}}{d t}+\frac{d l_{3}}{d t}=0$

$-5+2(-5)+\frac{d l}{d t}=0$

$\frac{d l_{3}}{d t}=15 m / s$

$\Rightarrow v_{B}=15 \mathrm{m} / \mathrm{s} \downarrow$

At a given instant, $A$ is moving with velocity of $5\,\,m/s$ upwards.What is velocity of $B$ at that time

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