Atomic weight of boron is $10.81$ and it has two isotopes $_5{B^{10}}$ and $_5{B^{11}}$. Then ratio of $ _5{B^{10}}{\,:\,_5}{B^{11}} $ in nature would be
Atomic weight of boron is $10.81$ and it has two isotopes $_5{B^{10}}$ and $_5{B^{11}}$. Then ratio of $ _5{B^{10}}{\,:\,_5}{B^{11}} $ in nature would be
- [AIPMT 1998]
- A
$19 : 81$
- B
$10 : 11$
- C
$15 : 16 $
- D
$81 : 19$
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- [JEE MAIN 2023]
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- [JEE MAIN 2021]