Borax has the molecular formula
$Na_2[B_4O_3(OH)_4].6H_2O$
$Na_2[B_4O_5(OH)_4].6H_2O$
$Na_2[B_4O_5(OH)_4].8H_2O$
$Na_2[B_4O_6(OH)_2].8H_2O$
The dissolution of $Al(OH)_3$ by a solution of $NaOH$ results in the formation of
$BF_3$ on hydrolysis forms
$(BN)_n$ exists in
$Be$ and $Al$ exhibit many properties which are similar, but the two elements differ in :
Given below are two statements :
Statement $I:$ Upon heating a borax bead dipped in cupric sulphate in a luminous flame, the colour of the bead becomes green.
Statement $II:$ The green colour observed is due to the formation of copper(I) metaborate.
In the light of the above statements, choose the most appropriate answer from the options given below :