Borax in its crystal possess

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Question

Borax $\left[\mathrm{Na}_{2}\left(\mathrm{B}_{4} \mathrm{O}_{5}(\mathrm{OH})_{4} \cdot 8 \mathrm{H}_{2} \mathrm{O}\right]\right.$

$\mathrm{Sp}^{2}

Vedclass · Accepted Answer

$2$ tetrahedral and $2$ planar triangular units

Vedclass · Answer

Borax $\left[\mathrm{Na}_{2}\left(\mathrm{B}_{4} \mathrm{O}_{5}(\mathrm{OH})_{4} \cdot 8 \mathrm{H}_{2} \mathrm{O}\right]\right.$

$\mathrm{Sp}^{2} \rightarrow$ trigonal planar

$\mathrm{Sp}^{3} \rightarrow$ tetrahedral

In borax $2\left(\mathrm{Sp}^{2}\right)$ trigonal planar and $2\left(\mathrm{Sp}^{3}\right)$ tetrahedral

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