Gujarati
Hindi
4-1.Newton's Laws of Motion
normal

Both the blocks shown here are of mass $m$ and are moving with constant velocity in direction shown in a resistive medium which exerts equal constant force on both blocks in direction opposite to the velocity. The tension in the string connecting both of them will be (Neglect friction)

A

$mg$

B

$mg / 2$

C

$mg / 3$

D

$mg / 4$

Solution

at Block B $T + F = mg$

at Block A $T = F$

$T =\frac{ Mg }{2}$

at Block $B$

$T + F = mg$

at Block $A$

$T = F$

$T =\frac{ Mg }{2}$

Standard 11
Physics

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