By Remainder Theorem remainder, when p(x) is divided by g(x), where p(x)=x^{3}-2 x^{2}-4 x-1, quad g

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2. Polynomials

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By Remainder Theorem find the remainder, when $p(x)$ is divided by $g(x),$ where

$p(x)=x^{3}-2 x^{2}-4 x-1, \quad g(x)=x+1$

A

$1$

B

$0$

C

$-1$

D

$2$

Solution

We have $g(x)=x+1$

$\Rightarrow x+1=0$

$\Rightarrow x=-0$

Remainder $= p (-1)$

$=(-1)^{3}-2(-1)^{2}-4(-1)=-1-2+4-1$

$=0$

Standard 9

Mathematics

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