By selling an article for Rs., 21, a man lost | vedclass

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Question

Let, the cost of article be $₹ x .$ At $x \%$ loss, the article sold at $₹ 21$

Now, according to the question, $x\left(\frac{100-x}{100}\right)=21

Vedclass · Accepted Answer

$30,70$

Vedclass · Answer

Let, the cost of article be $₹ x .$ At $x \%$ loss, the article sold at $₹ 21$

Now, according to the question, $x\left(\frac{100-x}{100}ight)=21 \Rightarrow x\left(1-\frac{x}{100}ight)=21$

$\Rightarrow x-\frac{x^{2}}{100}=21 \Rightarrow x^{2}-100 x+2100=0$

$\Rightarrow \quad(x-30)(x-70)=0$

$	herefore \quad x=Rs. 30 \quad$ or, $\quad Rs. 70$

By selling an article for $Rs.\, 21,$ a man lost such that the percentage loss was equal to the cost price. The cost price of the article was (in $Rs.$)

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