Calculate solubility of AgCl (s) in 0.1,M,NaCl at 25,^oC., {K_{sp}}(AgCl) = 2.8 × {10^{ - 10}}

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6-2.Equilibrium-II (Ionic Equilibrium)

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Calculate the solubility of $AgCl$(s) in $0.1\,M\,NaCl$at $25\,^oC.\,$ ${K_{sp}}(AgCl) = 2.8 \times {10^{ - 10}}$

A

$3.0 \times {10^{ - 8}}\,M{L^{ - 1}}$

B

$2.5 \times {10^{ - 7}}\,M{L^{ - 1}}$

C

$2.8 \times {10^{ - 9}}\,M{L^{ - 1}}$

D

$2.5 \times {10^7}\,M{L^{ - 1}}$

Solution

(c) $\frac{{2.8 \times {{10}^{ – 10}}}}{{0.1}} = 2.8 \times {10^{ – 9}}\,M{L^{ – 1}}$.

Standard 11

Chemistry

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