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Complete the following chemical equations :
$Z + 3LiAl{H_4} \to X + 3LiF + 3Al{F_3}$
$X + 6{H_2}O \to Y + 6{H_2}$
$3X + 3{O_2}\xrightarrow{\Delta }{B_2}{O_3} + 3{H_2}O$
Solution
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$(i)$ $4 \mathrm{BF}_{3}+3 \mathrm{LiAlH}_{4} \rightarrow \underset{\text { Diborane }(\mathrm{X})}{2 \mathrm{~B}_{2} \mathrm{H}_{6}}+3 \mathrm{LiF}+3 \mathrm{AlF}_{3}$
$(ii)$ $\mathrm{B}_{2} \mathrm{H}_{6}+6 \mathrm{H}_{2} \mathrm{O} \rightarrow 2 \mathrm{H}_{2} \mathrm{BO}_{3}+6 \mathrm{H}_{2}$
$(iii$) $\mathrm{B}_{2} \mathrm{H}_{6}+3 \mathrm{O}_{2} \stackrel{\Delta}{\longrightarrow} \mathrm{B}_{2} \mathrm{O}_{3}+3 \mathrm{H}_{2} \mathrm{O}$
$\mathrm{Z}=\mathrm{BF}_{3}, \mathrm{X}=\mathrm{B}_{2} \mathrm{H}_{6}$ and $\mathrm{Y}=\mathrm{B}(\mathrm{OH})_{3}$ or $\mathrm{H}_{3} \mathrm{BO}_{3}$