Consider an electric field $\vec{E}=E_0 \hat{x}$, where $E_0$ is a constant. The flux through the shaded area (as shown in the figure) due to this field is
$2 E_0 a^2$
$\sqrt{2} E_0 a^2$
$E_0 a^2$
$\frac{E_0 a^2}{\sqrt{2}}$
A field line shown in the figure. This field line cannot represent
An infinitely long uniform line charge distribution of charge per unit length $\lambda$ lies parallel to the $y$-axis in the $y-z$ plane at $z=\frac{\sqrt{3}}{2} a$ (see figure). If the magnitude of the flux of the electric field through the rectangular surface $A B C D$ lying in the $x-y$ plane with its center at the origin is $\frac{\lambda L }{ n \varepsilon_0}\left(\varepsilon_0=\right.$ permittivity of free space $)$, then the value of $n$ is
Electric flux through surface $s_1$
A charge $Q$ is placed at a distance $a/2$ above the centre of the square surface of edge $a$ as shown in the figure. The electric flux through the square surface is
A sphere encloses an electric dipole with charge $\pm 3 \times 10^{-6} \;\mathrm{C} .$ What is the total electric flux across the sphere?......${Nm}^{2} / {C}$