Dimensions of frac{1}{{{μ _0}{varepsilon _0}}} , where symbols have their usual meaning, are

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1.Units, Dimensions and Measurement

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Dimensions of $\frac{1}{{{\mu _0}{\varepsilon _0}}}$, where symbols have their usual meaning, are

A$[L{T^{ - 1}}]$

B$[{L^{ - 1}}T]$

C$[{L^{ - 2}}{T^2}]$

D$[{L^2}{T^{ - 2}}]$

Solution

(d) $C = \frac{1}{{\sqrt {{\mu _0}{\varepsilon _0}} }} \Rightarrow \frac{1}{{{\mu _0}{\varepsilon _0}}} = {c^2} = [{L^2}{T^{ – 2}}]$

Standard 11

Physics

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