During an experiment an ideal gas is found to obey an additional law $VP^2 =$ constant. The gas is initially at temperature $T$ and volume $V$. What will be the temperature  of the gas when it expands to a volume $2V$?

  • A

    $T' = \sqrt 4 \,T$

  • B

    $T' = \sqrt 2 \,T$

  • C

    $T' = \sqrt 5 \,T$

  • D

    $T' = \sqrt 6 \,T$

Similar Questions

A termodynamic system is taken through the closed cycle $PQRSP$ process. The net work done by the system is ...... $J$

A vessel contains an ideal monoatomic gas which expands at constant pressure, when heat $Q$ is given to it. Then the work done in expansion is : 

Gas obey $P^2V =$ constant. The initial temperature and volume are $T_0$ and $V_0$. If gas expands to volume $2V_0$, its final temperature becomes

The efficiency of reversible engine is the irreversible engine.

A monoatomic ideal gas, initially at temperature $T_1$, is enclosed in a cylinder fitted with a frictionless piston. The gas is allowed to expand adiabatically to a temperature $T_2$ by releasing the piston suddenly. If $L_1$ and $L_2$ are the lengths of the gas column before and after expansion respectively, then $T_1/T_2$ is given by