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7.Gravitation
medium
During motion of a man from equator to pole of earth, its weight will ....... $\%$ (neglect the effect of change in the radius of earth)
A
Increase by $0.34$
B
Decrease by $0.34$
C
Increase by $0.52$
D
Decrease by $0.52$
Solution
(a)
$w_{e q}=m g-m \omega^2 R_e$
$w_\rho=m g$
$\frac{w_p-w_{e q}}{w_{\text {eq }}}=\frac{m \omega^2 R}{m g-m \omega^2 R}$
$=\frac{\omega^2 R}{g-\omega^2 R} \quad\left[\omega^2 R=0.0337 \,m / s ^2\right]$
$\Rightarrow \frac{\Delta w}{w_{e q}}=\frac{0.0337}{9.81-0.0337}=0.3447 \times 10^{-2}$
$\Rightarrow \frac{\Delta w}{w_{e q}} \times 100=0.3447$
$\Rightarrow \text { Increases by } 0.34 \%$
Standard 11
Physics
