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4.Chemical Bonding and Molecular Structure
medium
During the change of $O _{2}$ to $O _{2}^{-}$, the incoming electron goes to the orbital :
A
$\pi 2 p_{y}$
B
$\sigma^{*} 2 p_{z}$
C
$\pi * 2 p_{x}$
D
$\pi 2 p_{x}$
(AIIMS-2019)
Solution
The electronic configuration of $O _{2}$ is,
$\sigma 1 s^{2} \sigma^{*} 1 s^{2} \sigma 2 s^{2} \sigma^{*} 2 s^{2} \sigma 2 p_{z}^{2} \pi 2 p_{x}^{2}=\pi 2 p_{y}^{2} \pi * 2 p_{x}^{1}=\pi * 2 p_{y}^{1}$
When electron is added in $O _{2}$ to form $O _{2}^{-},$ the added electron goes to $\pi * 2 p_{x}$ or $\pi * 2 p_{y}$
Thus, option $( C )$ is correct.
Standard 11
Chemistry
Similar Questions
Match each of the diatomic molecules in Column $I$ with its property / properties in Column $II$.
| Column $I$ | Column $II$ |
| $(A)$ $\mathrm{B}_2$ | $(p)$ Paramagnetic |
| $(B)$ $\mathrm{N}_2$ | $(q)$ Undergoes oxidation |
| $(C)$ $\mathrm{O}_2^{-}$ | $(r)$ Undergoes reduction |
| $(D)$ $\mathrm{O}_2$ | $(s)$ Bond order $\geq 2$ |
| $(t)$ Mixing of ' $\mathrm{s}$ ' and ' $\mathrm{p}$ ' orbitals |
