Each of two large conducting parallel plates has one sided surface area A . If one of plates is give

English

Gujarati

Hindi

1. Electric Charges and Fields

medium

Each of two large conducting parallel plates has one sided surface area $A$. If one of the plates is given a charge $Q$ whereas the other is neutral, then the electric field at a point in between the plates is given by

A

$\frac{Q}{A \varepsilon_0}$

B

$\frac{Q}{2 A \varepsilon_0}$

C

$\frac{Q}{4 A \varepsilon_0}$

D

Zero

Solution

(b)

$E_{\text {net }}=\frac{Q}{4 A \varepsilon_0} \times 2$

$=\frac{Q}{4 A \varepsilon_0}$

Standard 12

Physics

Share

Similar Questions

Three charges $q_1 = 1\,\mu c, q_2 = 2\,\mu c$ and $q_3 = -3\,\mu c$ and four surfaces $S_1, S_2 ,S_3$ and $S_4$ are shown in figure. The flux emerging through surface $S_2$ in $N-m^2/C$ is

medium

An infinitely long uniform line charge distribution of charge per unit length $\lambda$ lies parallel to the $y$-axis in the $y-z$ plane at $z=\frac{\sqrt{3}}{2} a$ (see figure). If the magnitude of the flux of the electric field through the rectangular surface $A B C D$ lying in the $x-y$ plane with its center at the origin is $\frac{\lambda L }{ n \varepsilon_0}\left(\varepsilon_0=\right.$ permittivity of free space $)$, then the value of $n$ is

medium

(IIT-2015)

A metallic shell has a point charge ‘$q$’ kept inside its cavity. Which one of the following diagrams correctly represents the electric lines of forces

easy

(IIT-2003)

A hollow cylinder has a charge $q$ coulomb within it. If $\phi$ is the electric flux in units of $volt-meter$ associated with the curved surface $B,$ the flux linked with the plane surface $A$ in units of $V-m$ will be

medium

(AIPMT-2007)

Gauss's law can help in easy calculation of electric field due to

easy