Each of two large conducting parallel plates has one sided surface area $A$. If one of the plates is given a charge $Q$ whereas the other is neutral, then the electric field at a point in between the plates is given by
$\frac{Q}{A \varepsilon_0}$
$\frac{Q}{2 A \varepsilon_0}$
$\frac{Q}{4 A \varepsilon_0}$
Zero
For a closed surface $\oint {\overrightarrow {E \cdot } } \,\overrightarrow {ds} \,\, = \,\,0$, then
In a cuboid of dimension $2 L \times 2 L \times L$, a charge $q$ is placed at the centre of the surface ' $S$ ' having area of $4 L ^2$. The flux through the opposite surface to ' $S$ ' is given by
A charge $Q$ is placed at a distance $a/2$ above the centre of the square surface of edge $a$ as shown in the figure. The electric flux through the square surface is
How field lines depend on area or on solid angle made by area ?
How does the no. of electric field lines passing through unit area depend on distance ?