Electric field at a point (x, y, z) is repres | vedclass

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Question

$\mathrm{V}-\mathrm{V}_{(0,0,0)}=\int_{0}^{1} \mathrm{E}_{\mathrm{x}} \mathrm{d} \mathrm{x}+\int_{0}^{1} \mathrm{E}_{\mathrm{y}} \mathrm{d} \mathrm{y}

Vedclass · Accepted Answer

$\frac{10}{3}$

Vedclass · Answer

$\mathrm{V}-\mathrm{V}_{(0,0,0)}=\int_{0}^{1} \mathrm{E}_{\mathrm{x}} \mathrm{d} \mathrm{x}+\int_{0}^{1} \mathrm{E}_{\mathrm{y}} \mathrm{d} \mathrm{y}$

$\mathrm{V}-2=\left[\mathrm{x}^{2}\right]_{0}^{1}+\frac{1}{3}\left[\mathrm{y}^{3}\right]_{0}^{1}$

$\mathrm{V}=2+1+\frac{1}{3}=\frac{10}{3} \mathrm{\,volt}$

Electric field at a point $(x, y, z)$ is represented by $\vec E = 2x\hat i + {y^2}\hat j$ if potential at $(0,0,0)$ is $2\, volt$ find potential at $(1, 1, 1)$

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