Solve using suitable identities : (998)^{3}

English

Gujarati

Hindi

2. Polynomials

hard

Evaluate using suitable identities : $(998)^{3}$

A

$894041942$

B

$894051922$

C

$9961196$

D

$994011992$

Solution

$(998)^{3}=(1000-2)^{3}$

$=(1000)^{3}-(2)^{3}-3(1000)(2)(1000-2)$

$=1000000000-8-6000(1000-2)$

$=1000000000-8-6000000+12000$

$=994011992$

Standard 9

Mathematics

Share

Similar Questions

From the following polynomials find out which of them has $(x-1)$ as a factor

$x^{3}-7 x^{2}+14 x-8$

medium

Dividing $p(x)=x^{2}+12 x+36$ by $(x+5)$ the remainder is…….

easy

Expand

$(3 x+7)(-3 x+7)$

easy

On dividing $p(x)=x^{3}+2 x^{2}-5 a x-7$ by $(x+1),$ the remainder is $R _{1}$ and on dividing $q(x)=x^{3}+a x^{2}-12 x+6$ by $(x-2), \quad$ the remainder is $R _{2} .$ If $2 R _{1}+ R _{2}=6,$ then find the value of $a$.

hard

Find the zero of the polynomial in each of the following cases

$q(y)=\pi y+3.14$

easy