Expand (4a -2b -3c)^2.

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2. Polynomials

medium

Expand $(4a -2b -3c)^2.$

Option A

Option B

Option C

Option D

Solution

Using Identity $V$, we have

$(4 a-2 b-3 c)^{2}=[4 a+(-2 b)+(-3 c)]^{2}$

$=(4 a)^{2}+(-2 b)^{2}+(-3 c)^{2}+2(4 a)(-2 b)+2(-2 b)(-3 c)+2(-3 c)(4 a)$

$=16 a^{2}+4 b^{2}+9 c^{2}-16 a b+12 b c-24 a c$

Standard 9

Mathematics

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