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$(2 x+5 y)^{2}$
$=(2 x)^{2}+2(2 x)(5 y)+(5 y)^{2}$
$=4 x^{2}+20 x y+25 y^{2}$
From the following polynomials find out which of them has $(x+1)$ as a factor
$x^{3}-2 x^{2}-5 x+6$
Factorise the following:
$\left(2 x+\frac{1}{3}\right)^{2}-\left(x-\frac{1}{2}\right)^{2}$
Without actually calculating the cubes, find the value of each of the following
$(14)^{3}+(27)^{3}-(41)^{3}$
Factorise each of the following
$27 x^{3}-8 y^{3}-54 x^{2} y+36 x y^{2}$
$4 x^{2}+20 x+25$
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