Explain the $\alpha -$ decay process and give its appropriate example
In the $\alpha$-decay phenomenon the unstable nucleus automatically converts and forms a new nucleus and emits $\alpha$-particles.
$\alpha$-particle is the nucleus of helium.
$\therefore \alpha={ }_{2} \mathrm{He}^{4}$
The disintegrating nucleus is called the parent nucleus and the newly formed nucleus is called the daughter nucleus.
In a $\alpha$-decay, the mass number of the product nucleus is four less than that of decaying nucleus
while the atomic number decreases by two.
The equation of $\alpha$-decay can be expressed as follows:
${ }_{\mathrm{Z}}^{\mathrm{A}} \mathrm{X} \rightarrow{ }_{\mathrm{Z}-2}^{\mathrm{A}-4} \mathrm{Y}+{ }_{2}^{4} \mathrm{He}+\mathrm{Q}$
$\text { where } X=\text { parent nucleus }$ $Y=\text { daughter nucleus }$
$Q=$Which is the total kinetic energy released in the process which can be determined from the relation of the mass and energy of the Einstein.
$\mathrm{Q}=\left[m_{\mathrm{X}}-m_{\mathrm{Y}}-m_{\mathrm{He}}\right] c^{2}$
where $m_{\mathrm{X}}=$ mass of parent nucleus
$m_{\mathrm{Y}}=$ mass of daughter nucleus
$m_{\mathrm{He}}=$ mass of $\alpha$-particle and
$c$ speed of light in vacuum
If original nucleus is at rest, $Q$ is the kinetic energy of the products.
As $Q>0$ for $\alpha$-decay, this process is exothermic process as a $Q<0$, this process is endothermic process.
If original nucleus is at rest, $\mathrm{Q}$ is the kinetic energy of the products.
As $\mathrm{Q}>0$ for $\alpha$-decay, this process is exothermic process as a $\mathrm{Q}<0$, this process is endothermic
process.
Example : The decay of ${ }_{92}^{238} \mathrm{U}$ to thorium ${ }_{90}^{234} \mathrm{Th}$ with emission of a helium nucleus ${ }_{2}^{4} \mathrm{He}$
( $\alpha$-particles) whose chemical equation,
${ }_{92}^{238} \mathrm{U} \rightarrow{ }_{90}^{234} \mathrm{~T} h+{ }_{2}^{4} \mathrm{H} e+\mathrm{Q}$
where $\mathrm{Q}$ is the emitted heat,
$\mathrm{Q}=\left[m_{\mathrm{U}}-m_{\mathrm{Th}}-m_{\mathrm{He}}\right] c^{2}$
The half-life of a radioactive nucleus is $5$ years, The fraction of the original sample that would decay in $15$ years is
Which sample, $A$ or $B$ shown in figure has shorter mean-life?
At any instant the ratio of the amount of radioactive substances is $2 : 1$. If their half lives be respectively $12$ and $16$ hours, then after two days, what will be the ratio of the substances
Half-life of a radioactive substance is $20$ minutes. Difference between points of time when it is $33\%$ disintegrated and $67\%$ disintegrated is approximately ........... $min$
In Fig. $X$ represents time and $Y$ represents activity of a radioactive sample. Then the activity of sample, varies with time according to the curve