Factorise $: 121 x^{2}-289 y^{2}$
$121 x^{2}-289 y^{2}=(11 x)^{2}-(17 y)^{2}$
$=(11 x-17 y)(11 x+17 y)$
The value of $249^{2}-248^{2}$ is
What should be subtracted from $p(x)=x^{2}+9 x+20,$ so that the resulting polynomial is divisible by $x+2 ?$
For the polynomial
$\frac{x^{3}+2 x+1}{5}-\frac{7}{2} x^{2}-x^{6},$ write
$(i)$ the degree of the polynomial
$(ii)$ the coefficient of $x^{3}$
$(iii)$ the coefficient of $x^{6}$
$(iv)$ the constant term
Expand
$\left(x-\frac{1}{2}\right)^{2}$
Without actually calculating the cubes, find the value of :
$\left(\frac{1}{2}\right)^{3}+\left(\frac{1}{3}\right)^{3}-\left(\frac{5}{6}\right)^{3}$
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