Factorise
$6 x^{3}+7 x^{2}-14 x-15$
$(x+1)(3 x+5)(2 x-3)$
By Remainder Theorem find the remainder, when $p(x)$ is divided by $g(x),$ where
$p(x)=x^{3}-2 x^{2}-4 x-1, \quad g(x)=x+1$
Dividing $x^{3}+125$ by $(x-5),$ the remainder is $\ldots \ldots \ldots .$
Check whether $p(x)$ is a multiple of $g(x)$ or not, where
$p(x)=x^{3}-x+1, \quad g(x)=2-3 x$
If $x+2 a$ is a factor of $x^{5}-4 a^{2} x^{3}+2 x+2 a+3,$ find $a$
Factorise $: x^{3}-x^{2}-17 x-15$
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