Gujarati
Hindi
3.Current Electricity
medium

Fig. shows rough sketch of meter bridge. $(G)$ deflects zero at length $l\, cm$. Now $R_1$ and $R_2$ are interchanged then balancing length increases by $25\, cm$. Find $R_1/R_2$ 

A

$\frac{3}{5}$

B

$\frac{2}{5}$

C

$\frac{2}{3}$

D

$\frac{5}{2}$

Solution

$\frac{\mathrm{R}_{1}}{\mathrm{R}_{2}}=\frac{\ell}{100-\ell}$ and $\frac{\mathrm{R}_{2}}{\mathrm{R}_{1}}=\frac{\ell+25}{75-\ell}$

So $\frac{\ell}{100-\ell}=\frac{\ell+25}{75-\ell}$ or $\ell=\frac{75}{2} \mathrm{\,cm}$

Standard 12
Physics

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