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Figure below shows a small mass connected to a string, which is attached to a vertical post. If the ball is released, when the string is horizontal as shown below. The magnitude of the total acceleration (including radial and tangential) of the mass as a function of the angle $\theta$ is

$g \sin \theta$
$g \sqrt{3 \cos ^2 \theta+1}$
$g \cos \theta$
$g \sqrt{3 \sin ^2 \theta+1}$
Solution

(d)
As ball falls through height $h$ and string turns by angle $\theta$,
Velocity of ball is obtained by equating kinetic and potential energies
$\Rightarrow \frac{1}{2} m v^2 =m g h$
$\Rightarrow v^2=2 g h$
$\Rightarrow v^2=2 g l \sin \theta$
So, radial acceleration is
$a_r=\frac{v^2}{l}=2 g \sin \theta$
'Tangential acceleration is produced by component of weight along the string.
$\therefore$ Tangential acceleration is
$a_t=g \cos \theta$
Hence, total acceleration is
$a=\sqrt{ a _t^2+ a _r^2}$
$=\sqrt{4 g^2 \sin ^2 \theta+g^2 \cos ^2 \theta}$
$=g\sqrt{1+3 \sin ^2 \theta}$