Figure shows three blocks in contact and kept | vedclass

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Question

Total mass of three blocks: $M=5+2+1=8 k g$

Acceleration of the blocks: $a=\frac{F}{M}=\frac{16}{8}=2$

Let $N_{A B}$ and $N_{B C}$ be the force

Vedclass · Accepted Answer

$3 : 1$

Vedclass · Answer

Total mass of three blocks: $M=5+2+1=8 k g$

Acceleration of the blocks: $a=\frac{F}{M}=\frac{16}{8}=2$

Let $N_{A B}$ and $N_{B C}$ be the force exerted by block $A$ on $B$ and by block $B$ on $\mathrm{C}$ respectively.

$F-N_{B A}=m_{A} a$ where $N_{A B}=N_{B A}$

$	herefore 16-N_{B A}=5 	imes 2=10$

$\Rightarrow N_{B A}=6=N_{A B}$

$N_{A B}-N_{C B}=m_{B} 	imes a=2 	imes 2=4$

$	herefore N_{C B}=N_{B C}=6-4=2$

$	herefore \frac{N_{A B}}{N_{B C}}=\frac{6}{2}=\frac{3}{1}$

Figure shows three blocks in contact and kept on a smooth horizontal surface. What is ratio of force exerted by block $A$ on $B$ to that of $B$ on $C$

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