2. Polynomials
easy

निम्नलिखित बहुपदों के लिए, $p(0), p(1)$ और $p(-2)$ ज्ञात कीजिए

$p(y)=(y+2)(y-2)$

Option A
Option B
Option C
Option D

Solution

We have $p(y)=(y+2)(y-2)=y^{2}-4$

$\therefore$ $p(0)=(0)^{2}-4$

$=0-4=-4$

And, $p(1)=(1)^{2}-4$

$=1-4=-3$

And, $\quad p(-2)=(-2)^{2}-4$

$=4-4=0$

Standard 9
Mathematics

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