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6.Interest
hard
Find the least number of complete years in which a sum of $Rs. 1500$ at $25 \%$ compound interest will be more than double.
A
$4$
B
$5$
C
$6$
D
$7$
Solution
Here, $P = Rs .1500, R =25 \% p \cdot a$
$n=?$ (No. of years) Now according to question:
$\Rightarrow P\left[\left(1+\frac{R}{100}\right)^{n}\right]>2 P \Rightarrow\left(1+\frac{25}{100}\right)^{n}>2 \Rightarrow\left(\frac{5}{4}\right)^{n}>2$
By hit and trial method, we get $\Rightarrow n=4$ years
Standard 13
Quantitative Aptitude
