Find the least number of complete years in wh | vedclass

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Question

Here, $P = Rs .1500, R =25 \% p \cdot a$

$n=?$ (No. of years) Now according to question:

$\Rightarrow P\left[\left(1+\frac{R}{100}\right)^{n}\ri

Vedclass · Accepted Answer

$4$

Vedclass · Answer

Here, $P = Rs .1500, R =25 \% p \cdot a$

$n=?$ (No. of years) Now according to question:

$\Rightarrow P\left[\left(1+\frac{R}{100}\right)^{n}\right]>2 P \Rightarrow\left(1+\frac{25}{100}\right)^{n}>2 \Rightarrow\left(\frac{5}{4}\right)^{n}>2$

By hit and trial method, we get $\Rightarrow n=4$ years

Find the least number of complete years in which a sum of $Rs. 1500$ at $25 \%$ compound interest will be more than double.

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