Find the number of electrons emitted per second by a $24 \,W$ source of monochromatic light of wavelength $6600 \mathring A$, assuming $3 \%$ efficiency for photoelectric effect (take $h=6.6 \times 10^{-34} \,Js$ ) $S$

  • A

    $48 \times 10^{19}$

  • B

    $48 \times 10^{17}$

  • C

    $8 \times 10^{19}$

  • D

    $24 \times 10^{17}$

Similar Questions

The incident photon involved in the photoelectric effect experiment.

$10^{-3} \, W$ of $5000\, \mathring A $ light is directed on a photoelectric cell. If the current in the cell is $0.16 \mu A$, the percentage of incident photons which produce photoelectrons, is.......$\%$

A $160 \,W$ infrared source is radiating light of wavelength $50000 \,\mathring A$ uniformly in all directions. The photon flux at a distance of $1.8 \,m$ is the order of ............. $m^{-2} s ^{-1}$

  • [KVPY 2015]

For photo-electric effect with incident photon wavelength $\lambda$, the stopping potential is $V _0$. Identify the correct variation$(s)$ of $V _0$ with $\lambda$ and $1 / \lambda$. $Image$

  • [IIT 2015]

A source $S_1$ is producing, $10^{15}$ photons per second of wavelength $5000 \;\mathring A.$ Another source $S_2$ is producing $1.02 \times 10^{15}$ photons per second of wavelength $5100\;\mathring A$. Then, $($ power of $S_2)/$  $($ power of $S_1)$ is equal to

  • [AIPMT 2010]