Find the value of the polynomial $3 x^{3}-4 x^{2}+7 x-5,$ when $x=3$
$36$
$61$
$26$
$81$
Let $p(x)=3 x^{2}-4 x^{2}+7 x-5$
$\therefore \quad p(3)=3(3)^{3}-4(3)^{2}+7(3)-5$
$=3(27)-4(9)+21-5$
$=81-36+21-5$
$=61$
Factorise
$144 x^{2}-289 y^{2}$
Expand
$(2 x-y-5)^{2}$
If $(x-1)$ is a factor of $x^{3}+7 x^{2}+a x-3,$ then find the value of $a$.
Find the value of each of the following polynomials at the indicated value of variables
$q(y)=5 y^{3}-4 y^{2}+14 y-\sqrt{3}$ at $y=2$
Factorise the following quadratic polynomials by splitting the middle term
$6 x^{2}+7 x-20$
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