મૂલ્ય શોધો. tan frac{19 π}{3}

English

Gujarati

Hindi

3.Trigonometrical Ratios, Functions and Identities

easy

મૂલ્ય શોધો. $\tan \frac{19 \pi}{3}$

A

$\sqrt{3}$

B

$\sqrt{3}$

C

$\sqrt{3}$

D

$\sqrt{3}$

Solution

It is known that the values of tan $x$ repeat after an interval of $n$ or $180^{\circ}.$

$\therefore \tan \frac{19 \pi}{3}=\tan 6 \frac{1}{3} \pi=\tan \left(6 \pi+\frac{\pi}{3}\right)=\tan \frac{\pi}{3}=\tan 60^{\circ}=\sqrt{3}$

Standard 11

Mathematics

Share

Similar Questions

${\sin ^6}\theta + {\cos ^6}\theta + 3{\sin ^2}\theta {\cos ^2}\theta = $

easy

સાબિત કરો કે : $\sin 3 x+\sin 2 x-\sin x=4 \sin x \cos \frac{x}{2} \cos \frac{3 x}{2}$

hard

જો $\sin \theta + \cos \theta = m$ અને $\sec \theta + {\rm{cosec}}\theta = n$, તો $n(m + 1)(m – 1) = $

easy

જો $x = \sec \theta + \tan \theta ,$ તો $x + \frac{1}{x} = $

easy

જો $\tan A + \cot A = 4,$ તો ${\tan ^4}A + {\cot ^4}A$ =

easy