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2. Polynomials
medium
Find the zeroes of the polynomial:
$p(x)=(x-2)^{2}-(x+2)^{2}$
A
$1$
B
$-1$
C
$-2$
D
$0$
Solution
Let $p(x)=(x-2)^{2}-(x+2)^{2}$
As fining a zero of $p ( x )$, is same as solving the equation $p ( x )=0$
So, $p(x)=0 \Rightarrow(x-2)^{2}-(x+2)^{2}=0$
$\Rightarrow(x-2+x+2)(x-2-x-2)=0$
$\Rightarrow 2 x(-4)=0 \Rightarrow-8 x=0 \Rightarrow x=0$
Hence, $x=0$ is the only one zero of $p(x)$
Standard 9
Mathematics
