For a moving body at any instant of time

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$(A)$ Suppose throwing a ball vertically up. At the highest point. It is at momentary rest $( V = O )$ i but acceleration $g$ still acts downwards. So

Vedclass · Accepted Answer

If displacement, velocity and acceleration at that instant are known, we can find the displacement at any given time in future

Vedclass · Answer

$(A)$ Suppose throwing a ball vertically up. At the highest point. It is at momentary rest $( V = O )$ i but acceleration $g$ still acts downwards. So, (A) is incorrect.

$(B)$ A slowing body has positive retardation.

$(C)$ Distance travelled is always positive, irrespective its motion.

$(D)$ From second law of kinematics,

$x=x_0+u t+\frac{1}{2} a^2$

By knowing $u , a$ and $x _0$ at instant $t =0$ we can determine $x$ at any $t$.

Similar Questions

A car is moving with speed of $150\,km / h$ and after applying the brake it will move $27\,m$ before it stops. If the same car is moving with a speed of one third the reported speed then it will stop after travelling $....m$ distance.

A small block slides without friction down an inclined plane starting from rest. Let ${S_n}$be the distance travelled from time $t = n - 1$ to $t = n.$ Then $\frac{{{S_n}}}{{{S_{n + 1}}}}$ is

A particle moves towards east with velocity $5\, m/s$. After $10$ seconds its direction changes towards north with same velocity. The average acceleration of the particle is

The velocity-time and acceleration-time graphs of a particle are given as Its position-time graph may be gvien as

The velocity of a particle moving in the positive direction of $x$-axis varies as $v=5 \sqrt{x}$. Assuming that at $t=0$, particle was at $x=0$. What is the acceleration of the particle $.........m/s^2$