For a perfect gas, two pressures P_{1} and P_{2} are shown in figure. graph shows

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12.Kinetic Theory of Gases

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For a perfect gas, two pressures $P_{1}$ and $P_{2}$ are shown in figure. The graph shows

A

$P _{1} > P _{2}$

B

$P _{1} < P _{2}$

C

$P _{1} = P _{2}$

D

Insufficient data to draw any conclusion

Solution

$PV = nRT$

$\frac{ V }{ T }=\frac{ nR }{ P }$

$\frac{ nR }{ P _{1}}<\frac{ nR }{ P _{2}}$

$P _{2} < P _{1}$

Standard 11

Physics

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