In a series $CR$ circuit shown in figure, the applied voltage is $10\, V$ and the voltage across capacitor is found to be $8V$. Then the voltage across $R$, and the phase difference between current and the applied voltage will respectively be

A circuit element $X$ when connected to an a.c. supply of peak voltage $100\,V$ gives a peak current of $5\,A$ which is in phase with the voltage. A second element $Y$ when connected to the same a.c. supply also gives the same value of peak current which lags behind the voltage by $\frac{\pi}{2}$. If $X$ and $Y$ are connected in series to the same supply, what will be the rms value of the current in ampere?

A $10 \mu \mathrm{F}$ capacitor is connected to a $210 \mathrm{~V}, 50 \mathrm{~Hz}$ source as shown in figure. The peak current in the circuit is nearly $(\pi=3.14)$ :

An inductor and a resistor in series are connected to an $A.C$. supply of variable frequency. As the frequency of the source is increased, the phase angle between current and the potential difference across $L$ will

When an ac generator of $120\,V$ is connected in series with a capacitor and a resistor of $30\,\Omega $, the circuit carries a current $1·5\,A$. The potential difference across the capacitor will be…..$V$