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5.Work, Energy, Power and Collision
medium
For the pulley system the kinetic energy of the $6\,kg$ block after $5\,s$ is ............ $\mathrm{J}$
A
$100$
B
$300$
C
$500$
D
$800$
Solution
$a=\frac{20}{10}=2 \mathrm{m} / \mathrm{s}^{2}$
$\mathrm{v}=\mathrm{at}=2 \times 5=10 \mathrm{m} / \mathrm{s}$
$\Rightarrow \mathrm{k}=\frac{1}{2} \mathrm{mv}^{2}=\frac{1}{2} \times 6 \times 10^{2}=300 \mathrm{J}$
Standard 11
Physics
