For the two events $A$ and $B$, $P(A) = 0.38,\,$ $P(B) = 0.41,$ then the value of $P(A$ not) is
$0.41$
$0.62$
$0.59$
$0.21$
One card is drawn from each of two ordinary packs of $52$ cards. The probability that at least one of them is an ace of heart, is
There are $n$ letters and $n$ addressed envelopes. The probability that all the letters are not kept in the right envelope, is
A die is thrown, find the probability of following events: A number less than $6$ will appear,
Consider the experiment of rolling a die. Let $A$ be the event 'getting a prime number ', $B$ be the event 'getting an odd number '. Write the sets representing the events $^{\prime}$ not $A\,^{\prime}$.
Two players play the following game: $A$ writes $3,5,6$ on three different cards: $B$ writes $8,9,10$ on three different cards. Both draw randomly two cards from their collections. Then, $A$ computes the product of two numbers helshe has drawn, and $B$ computes the sum of two numbers he/she has drawn. The player getting the larger number wins. What is the probability that A wins?