Gujarati
14.Probability
normal

For the two events $A$ and $B$, $P(A) = 0.38,\,$ $P(B) = 0.41,$ then the value of $P(A$ not) is

A

$0.41$

B

$0.62$

C

$0.59$

D

$0.21$

Solution

(b) $P(\bar A) = 1 – 0.38 = 0.62.$

Standard 11
Mathematics

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