Four identical point masses 'm' joined by light string of length 'l' arrange such th

English

Gujarati

Hindi

3-2.Motion in Plane

medium

Four identical point masses $'m'$ joined by light string of length $'l'$ arrange such that they form square frame. Centre of table is coincide with centre of arrangment. If arrangement rotate with constant angular velocity $'\omega '$ , find out tension in each string

A$\frac{{m{\omega ^2}l}}{4}$

B$m{\omega ^2}l/2$

C$m{\omega ^2}l/\sqrt 2 $

D$m{\omega ^2}l$

Solution

$T\sqrt 2 = \frac{{m{\omega ^2}l}}{{\sqrt 2 }}$

Standard 11

Physics

Share

Similar Questions

A ball of mass $0.1\, Kg$. is whirled in a horizontal circle of radius $1\, m$. by means of a string at an initial speed of $10\, R.P.M.$ Keeping the radius constant, the tension in the string is reduced to one quarter of its initial value. The new speed is ……. $r.p.m.$

easy

A mass is supported on a frictionless horizontal surface. It is attached to a string and rotates about a fixed centre at an angular velocity ${\omega _0}$. If the length of the string and angular velocity are doubled, the tension in the string which was initially ${T_0}$ is now

easy

(AIIMS-1985)

The force required to keep a body in uniform circular motion is

easy

One end of string of length $l$ is connected to a particle of mass $'m'$ and the other end is connected to a small peg on a smooth horizontal table. If the particle moves in circle with speed $'v',$ the net force on the particle (directed towards centre) will be ($T$ represents the tension in the string)

easy

(NEET-2017)

A motorcycle is going on an overbridge of radius $R$. The driver maintains a constant speed. As the motorcycle is ascending on the overbridge, the normal force on it

easy